Equation of the Plane that Passes Through a Point
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Find an equation of the plane that passes through the point (6,0,-2) and contains the line x = 4 - 2t, y = 3 + 5t, z = 7 + 4t.
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Solution Summary
The solution finds an equation that passes through the point (6,0,-2) and contains the line x = 4 - 2t, y = 3 + 5t, z = 7 + 4t.
Solution Preview
The trick is to find a vector normal to the plane.
To find a normal to the plane, you have to find two vectors in the plane and take their cross product. The result is a vector perpendicular to both.
How to find two vectors in the plane.
Choose three points in the plane, draw arrows from the ...
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