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Equation of the Plane that Passes Through a Point

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Find an equation of the plane that passes through the point (6,0,-2) and contains the line x = 4 - 2t, y = 3 + 5t, z = 7 + 4t.

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Solution Summary

The solution finds an equation that passes through the point (6,0,-2) and contains the line x = 4 - 2t, y = 3 + 5t, z = 7 + 4t.

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The trick is to find a vector normal to the plane.
To find a normal to the plane, you have to find two vectors in the plane and take their cross product. The result is a vector perpendicular to both.
How to find two vectors in the plane.
Choose three points in the plane, draw arrows from the ...

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