# Sketch Hyperbola after Finding Center, Vertex and Foci of the Equation

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Sketch hyperbola after finding Center, Vertex and Foci of this equation: (y+5)squared/16 - xsquared/9 =1

Please show steps needed

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##### Solution Summary

An hyperbola is sketched. The center, vertex and foci are calculated and depicted on the graph.

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Eqn. of hyperbola:

{(y+5)^2/16} - {x^2/9} = 1 .......(1)

This Eqn. Can be written interms of transformed axes (X,Y) as,

Y^2/4^2 - X^2/3^2 = 1 ........(2)

where,

Y = y+5; and X = x

compare Eqn. ...

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