Explore BrainMass

Explore BrainMass

    Sketch Hyperbola after Finding Center, Vertex and Foci of the Equation

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Sketch hyperbola after finding Center, Vertex and Foci of this equation: (y+5)squared/16 - xsquared/9 =1
    Please show steps needed

    © BrainMass Inc. brainmass.com March 6, 2023, 12:48 pm ad1c9bdddf

    Solution Preview

    Eqn. of hyperbola:
    {(y+5)^2/16} - {x^2/9} = 1 .......(1)
    This Eqn. Can be written interms of transformed axes (X,Y) as,
    Y^2/4^2 - X^2/3^2 = 1 ........(2)
    Y = y+5; and X = x

    compare Eqn. ...

    Solution Summary

    An hyperbola is sketched. The center, vertex and foci are calculated and depicted on the graph.