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    Sketch Hyperbola after Finding Center, Vertex and Foci of the Equation

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    Sketch hyperbola after finding Center, Vertex and Foci of this equation: (y+5)squared/16 - xsquared/9 =1
    Please show steps needed

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    https://brainmass.com/math/vector-calculus/sketch-hyperbola-center-vertex-foci-equation-19122

    Solution Preview

    Eqn. of hyperbola:
    {(y+5)^2/16} - {x^2/9} = 1 .......(1)
    This Eqn. Can be written interms of transformed axes (X,Y) as,
    Y^2/4^2 - X^2/3^2 = 1 ........(2)
    where,
    Y = y+5; and X = x

    compare Eqn. ...

    Solution Summary

    An hyperbola is sketched. The center, vertex and foci are calculated and depicted on the graph.

    $2.49

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