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Sketch Hyperbola after Finding Center, Vertex and Foci of the Equation

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Sketch hyperbola after finding Center, Vertex and Foci of this equation: (y+5)squared/16 - xsquared/9 =1
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Solution Summary

An hyperbola is sketched. The center, vertex and foci are calculated and depicted on the graph.

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Eqn. of hyperbola:
{(y+5)^2/16} - {x^2/9} = 1 .......(1)
This Eqn. Can be written interms of transformed axes (X,Y) as,
Y^2/4^2 - X^2/3^2 = 1 ........(2)
Y = y+5; and X = x

compare Eqn. ...

Solution provided by:
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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