# Differentiation of inverse trigonometric functions

Angular rate of change: A television camera at ground level is filming the lift-off of a space shuttle at a point 750 meters from the launch pad. Let (theta) be the angle of elevation of the shuttle and let s be the distance between the camera and the shuttle. Write (theta) as a function of s for the period of time when the shuttle is moving vertically. Differentiate the result to find d(theta)/dt in terms of s and ds/dt.

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The shape is a right triangle. s is the hypotenuse. One leg is 750 meters. (theta) is the ...

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The solution shows how to determine angular rate of change.

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