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Trigonometry : Circumference, Bearings, Perimeter of Octagon, Length of Shadow and Diameter of a Pipe

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1. Find the length L from point A to the top of the pole.

SEE ATTACHMENT FOR MORE REQUIRED INFO

2. Lookout station A is 15 km west of station B. The bearing from A to a fire directly south of B is S 37°50' E. How far is the fire from B?

3. The wheels of a car have a 24-in. diameter. When the car is being driven so that the wheels make 10 revolutions per second, how far with the car travel in one minute?

4. A regular octagon is inscribed in a circle of radius 15.8 cm. Find the perimeter of the octagon.

5. What is the angle of elevation of the sun when a 35-ft mast casts a 20-ft shadow?

6. A V-gauge is used to find the diameters of pipes. In the figure on p. 373 in the text, the measure of angle AVB is 54°. A pipe is placed in the V-shaped slot and the distance VP is used to predict the diameter. PLEASE SEE ATTACHMENT

Suppose that the diameter of a pipe is 2 cm. What is the distance VP?
Suppose that the distance VP is 3.93 cm. What is the diameter of the pipe?
Find the formula for d in terms of VP.
Find a formula for VP in terms of d.
The line VP is calibrated by listing the corresponding diameters as its units. This, in effect, establishes a function between VP and d.

Please add your file.

Reference:
Bittinger, M. L., & Beecher, J. A. (2000). Trigonometry update. Reading, MA: Addison Wesley.

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Solution Summary

Circumference, Bearings, Perimeter of Octagon, Length of Shadow and Diameter of a Pipe are investigated. The solution is detailed and well presented. Diagrams are included.

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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
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