Real analysis
Not what you're looking for? Search our solutions OR ask your own Custom question.
Show that if K is compact, then sup K and inf K both exist and are elements of K
© BrainMass Inc. brainmass.com March 6, 2023, 12:50 pm ad1c9bdddfhttps://brainmass.com/math/real-analysis/real-analysis-27081
Solution Preview
Proof:
Since each compact set is a bounded closed set. So K is bounded and ...
Solution Summary
This is a proof regarding the supermem and infimum of k.
$2.49