# Real analysis

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Show that if K is compact, then sup K and inf K both exist and are elements of K

Â© BrainMass Inc. brainmass.com March 6, 2023, 12:50 pm ad1c9bdddfhttps://brainmass.com/math/real-analysis/real-analysis-27081

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Proof:

Since each compact set is a bounded closed set. So K is bounded and ...

#### Solution Summary

This is a proof regarding the supermem and infimum of k.

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