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    Real analysis

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    Show that if K is compact, then sup K and inf K both exist and are elements of K

    © BrainMass Inc. brainmass.com February 24, 2021, 2:32 pm ad1c9bdddf
    https://brainmass.com/math/real-analysis/real-analysis-27081

    Solution Preview

    Proof:
    Since each compact set is a bounded closed set. So K is bounded and ...

    Solution Summary

    This is a proof regarding the supermem and infimum of k.

    $2.19

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