Define µ : Z4 × Z6 -> Z4 × Z3 by
µ ([x]4,[y]6) = ([x+2y]4,[y]3).
(a) Show that µ is a well-defined group homomorphism.
(b) Find the kernel and image of µ, and apply the fundamental homomorphism theorem.
Please see attached file.
(a) If y1 y2 (mod 6), then 2y1 - 2y2 is divisible by 12, so
2y1 2y2 (mod 4), and then it ...
This is a proof regarding a well-defined group homomorphism, and shows how to find kernel and image.