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    Diagonalizable

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    Suppose A is diagonalizable with distinct eigenvalues...

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    © BrainMass Inc. brainmass.com March 4, 2021, 5:36 pm ad1c9bdddf
    https://brainmass.com/math/linear-algebra/diagonalizable-matrix-orthogonal-projections-2544

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    I will use the notation a1...ak for the eigenvalues (rather than using lambda, which is difficult to write).
    I will also denote just by m the minimal polynomial of A. We know that because A is diagonalisable:
    m(t)=(t-a1)*...*(t-ak)
    So P_j(t)=(t-a1)*...*(t-ak)/c_j where in the product the factor (t-aj) is missing, as it ...

    Solution Summary

    This is a proof regarding a diagonalizable matrix and orthogonal projections.

    $2.49

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