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Integrals : Average Value of a Function over an Interval

13. What is the average value of the function f(x) = x sin(x2) over the interval [2,4]?

A. sin 4 + 2 sin 16 B. -sin 4 + 2 sin 16 C. (cos 4 - cos 16)/2
D. (cos 4 - cos 16)/4 E. (-cos 4 + cos 16)/4

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This is actually a question of integral:
∫x sin(x2)dx
= ∫0.5(dx2 ...

Solution Summary

The Average Value of a Function over an Interval is found.

$2.19