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Integration : Area of a Bounded Region

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Please help with the following problem. Provide step by step calculations for each.

The average value of f(x) = 1/x on the interval [4, 16] is

(ln 2)/3
(ln 2)/6
(ln 2)/12
3/2
0
1
none of these

Find the area, in square units, of the region bounded by the the x axis and the function y = 16 - x^2.

32/3
36
256/3
500/3
972
none of these

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Solution Summary

The area of a bounded region is found using integrals. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question. Step by step calculations are given.

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21. The average value of f(x) = 1/x on the interval [4, 16] is

(ln 2)/3
(ln 2)/6
(ln 2)/12
3/2
0
1
none of these

The answer is (ln 2)/6.

As by the definition, the average value of f(x) = 1/x on the interval [4, 16] is equal to the definite ...

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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
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  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
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  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
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