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18. Let

F(x) = ∫0 to x^1/3 (√1+t^4) dt

Then F'(0) =
A. 0 B. 1/3 C. 2/3
D. 1 E. Does not exist.

Please see attachment for full question.

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Solution Summary

An integral is solved.

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F(x) = integral (0, x^(1/3)) [sqrt(1 + t^2) * dt]

To find out, F'(0) = ?

F(x) = ...

Solution provided by:
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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