# Conic Surfaces and Surface Integrals

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Let S be the conic surface z = 3 sqrt (x^2 + y^2), where z is greater than or equal to 0 and less than or equal to 3. Find (double integral over S) z dS.

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Let S be the conic surface z = 3 sqrt (x^2 + y^2), ...

#### Solution Summary

Conic surfaces and surface integrals are investigated. The expert finds the double integral over S.

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