Find the numbers b such that the average value of f(x)=2+6x-3x^2 on the interval [0,b] is equal to 3.
This is actually an evaluation of the integral
∫f(x)= ∫2+6x-3x^2 dx in the [0, b] ...
The bound of an interval that allows for a certain average value of a function is found. The solution is detailed and well presented. The response received a rating of "5" from the student who originally posted the question.