Explore BrainMass

Explore BrainMass

    Groups : Symmetry

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Note: G' means derived (commutator) subgroup of G and Sn is symmetric group of degree n

    Please find G' in each case
    (a) G is abelian
    (b) G = Sn

    © BrainMass Inc. brainmass.com March 6, 2023, 1:19 pm ad1c9bdddf

    Solution Summary

    A proof involving symmetric groups is offered. The proof is concise.