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Groups and Subgroups : Indicies

If K is a normal subgroup of G has index m, show that g^m belongs to K for all g belonging to G.

Solution Preview

Proof. Since K is a normal subgroup of G has index m, we have
xK=Kx
for all x belonging to G. So, ...

Solution Summary

A proof involving subgroups and indicies is offered. The proof is concise.

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