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    Groups and Subgroups : Indicies

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    If K is a normal subgroup of G has index m, show that g^m belongs to K for all g belonging to G.

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    Solution Preview

    Proof. Since K is a normal subgroup of G has index m, we have
    xK=Kx
    for all x belonging to G. So, ...

    Solution Summary

    A proof involving subgroups and indicies is offered. The proof is concise.

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