Let X be a path-connected space and suppose that every map f: S^1 --> X is homotopically trivial but not necessarily by a homotopy leaving the base point x_0 fixed. Show that pi_1(X,x_0) = 0.© BrainMass Inc. brainmass.com April 1, 2020, 11:26 am ad1c9bdddf
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Some standard results:
1) Suppose X is a space, and x0 is a point of X. We define 1(X, x0) as homotopy classes of maps f: [0, 1] X, such that f (0) = f (1) = x0.
In other-words, homotopy means that one views as equivalent two maps which lie on a 1-parameter family of functions ft [0,1] X which satisfy the boundary conditions ft(0) = ft(1) = x0.
So, we call 1(X, x0) as fundamental group of X, if X is path connected.
2) We say a space is "simply connected" if its fundamental group is trivial.
3) Covering space: A map p: X Y is a covering map if around each point y in Y there exists a neighborhood Ny of b, so that ...
Fundamental Groups, Path-Connected Space, Connectivity and Homotopy are investigated. The solution is detailed and well presented. The response received a rating of "5" from the student who originally posted the question.