Parabola - Vertex, Intercepts

Related BrainMass Solutions

• Finding Vertex and Intercepts for a Parabola

  Hence, two x-intercepts are (-1, 0) and (-2,0). See a sketch of the graph below. Vertex and intercepts of a parabola are found. Vertex and intercepts for a parabola is found.

• parabola open upward or downward

  262421 parabola open upward or downward Solve the 2 problems. Show your work. 1. y = x ^2 - 4x -12 a) What is the vertex? b) What are the intercepts? c) Does the parabola open upward or downward?

• the x-intercept(s) and the coordinates of the vertex for the parabola.

  x-intercepts = vertex= for the x-intercepts: y = 0 so we need to solve the quadratic equation So Then x-intercepts are: (-6, 0) and (2, 0) Vertex: The x-coordinate of the parabola is Then substitute -2 for x to find its y-coordinate

• Does the parabola open upward or downward?

  113121 Does the parabola open upward or downward? Determine if the parabola for the equation, y = -2x^2 - 4x + 6, opens upward or downward. Find the vertex, x-intercepts, and y-intercept without graphing.

• Finding the Equation of a Parabola

  A parabola has x - intercepts of 3 and 7, a y - intercept at - 21 and (5,4) for its vertex. Write the parabola's equation.

• Functions and Parabolas : Intercepts, Vertex, Line of Symmetry and Image Set

  b) Using your answer to part (a), or otherwise, write down the coordinates of the vertex of the parabola. c) Find the x-intercepts and the y-intercept of the parabola.

• How to find vertex and intercepts for quadratic equations

  50982 How to find vertex and intercepts for quadratic equations Problem: Find the vertex and intercepts for y = x^2 + x - 6 Vertex: The vertex of the graph of y = a x2 + b x + c is the point where the axis of symmetry meets the parabola itself.

• Finding the vertex and intercepts of a parabola.

  113212 Finding the vertex and intercepts of a parabola. Find the vertex and intercepts for each parabola. Graph using Microsoft Excel.

• vertex, intercepts and ragne of parabola

  198294 vertex, intercepts and range of parabola See the attached problems 1. find the intercept, vertex, domain, and range, then graph the parabola (1) y = x^2 + 2x - 3 (2) y = -x^2 -5x - 4 (3) a = b^2 -6b - 16 2. graph the parabola, state

• Graphing Functions: Completing the Square, Quadratic Functions, Axis of Symmetry, and Intercepts

  This parabola has a vertex at We see that as the function approaches , so the vertex point is a maxima (the parabola opens down).