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    Transform the equation to standard form and find the center and radius of the circle:

    1. (x - 3)^2 = 9 - y^2

    2. x^2 + y^2 = 6x - 8y

    3. 2x^2 + 2y^2 = 2x + 2y - 1

    4. (x + 1)^2 + (y - 2)^2 = 25

    © BrainMass Inc. brainmass.com December 24, 2021, 8:55 pm ad1c9bdddf
    https://brainmass.com/math/geometry-and-topology/equation-standard-form-326529

    SOLUTION This solution is FREE courtesy of BrainMass!

    Transform the equation to standard form and find the center and radius of the circle:

    1.

    This can be written as . This is the required standard form.
    From the given form of the equation, , we have the center =(3, 0) and radius 3
    2.
    This can be written as . This is the required standard form.
    Further this can be written as
    Hence the center is (3, 4) and the radius is 5

    3.
    This can be written as . This is the required standard form.
    Further, this can be written as . This gives
    Hence the center is and radius 0.

    4. .
    Clearly, the center is (-1, 2) and radius 5
    This can be further written as
    Hence is the equation in standard form

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 8:55 pm ad1c9bdddf>
    https://brainmass.com/math/geometry-and-topology/equation-standard-form-326529

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