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# equation in standard form

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Transform the equation to standard form and find the center and radius of the circle:

1. (x - 3)^2 = 9 - y^2

2. x^2 + y^2 = 6x - 8y

3. 2x^2 + 2y^2 = 2x + 2y - 1

4. (x + 1)^2 + (y - 2)^2 = 25

https://brainmass.com/math/geometry-and-topology/equation-standard-form-326529

## SOLUTION This solution is FREE courtesy of BrainMass!

Transform the equation to standard form and find the center and radius of the circle:

1.

This can be written as . This is the required standard form.
From the given form of the equation, , we have the center =(3, 0) and radius 3
2.
This can be written as . This is the required standard form.
Further this can be written as
Hence the center is (3, 4) and the radius is 5

3.
This can be written as . This is the required standard form.
Further, this can be written as . This gives
Hence the center is and radius 0.

4. .
Clearly, the center is (-1, 2) and radius 5
This can be further written as
Hence is the equation in standard form

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