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Angles and Degrees

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Determine the angle when (6 angle (120deg))*(-4+jb+2*exp(j*15))=a+jb
Note: These angles are in degrees.

Possible choices:
a. -21.3
b. -12.1
c. -3
d. -2.07

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Solution Summary

This solution calculates the exact angle in degrees, when certain parameters are given.

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(6 angle (120deg))*(-4+jb+2*exp(j*15))=a+jb
=6(cos(120) + jsin(120))*(-4 + jb +2*cos(15) + j2*sin(15)) = a + jb
=6(-0.5 + 0.866j)*(-4 + jb +1.932 + 0.518j) = a + jb
=6(-0.5 + ...

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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