Proof about Ordering the Real Numbers
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Given any two real numbers x < y, we can find a rational number q such that
x < q< y.
Hint: you can prove this by using the following statement: for any positive real number x > 0 there exists a positive integer N such that x > 1/N > 0
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This solution explains how to provide proof about the ordering of the given real numbers.
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Given any two real numbers x < y, we can find a rational number q such that x < q< y.
Hint: you can prove this by using the following statement: for any positive real number x > 0 there exists a positive integer N such that x > 1/N > ...
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