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    Proof without using commutative axioms

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    How would the following proof be detailed if the commutative axioms did not exist? Explain your answer.

    Prove that for all real numbers r, s, t, and u:

    (r + s)(t + u) = rt + ru + st + su

    Commutative Axiom for Multiplication:
    For any two real numbers r and s, the following equation holds:
    rs = sr

    Commutative Axiom for Addition:
    For any two real numbers r and s, the following equation holds:
    r+s = s+r

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    Solution Preview

    For any three real numbers a, b, c, we have two distributive axioms for multiplication over ...

    Solution Summary

    Proof without using commutative axioms is typified.

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