Proof without using commutative axioms
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How would the following proof be detailed if the commutative axioms did not exist? Explain your answer.
Prove that for all real numbers r, s, t, and u:
(r + s)(t + u) = rt + ru + st + su
Commutative Axiom for Multiplication:
For any two real numbers r and s, the following equation holds:
rs = sr
Commutative Axiom for Addition:
For any two real numbers r and s, the following equation holds:
r+s = s+r
https://brainmass.com/math/discrete-math/proof-without-commutative-axioms-365508
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For any three real numbers a, b, c, we have two distributive axioms for multiplication over ...
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Proof without using commutative axioms is typified.
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