Proof without using commutative axioms
How would the following proof be detailed if the commutative axioms did not exist? Explain your answer.
Prove that for all real numbers r, s, t, and u:
(r + s)(t + u) = rt + ru + st + su
Commutative Axiom for Multiplication:
For any two real numbers r and s, the following equation holds:
rs = sr
Commutative Axiom for Addition:
For any two real numbers r and s, the following equation holds:
r+s = s+r
https://brainmass.com/math/discrete-math/proof-without-commutative-axioms-365508
Solution Preview
For any three real numbers a, b, c, we have two distributive axioms for multiplication over ...
Solution Summary
Proof without using commutative axioms is typified.
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