Proof without using commutative axioms
Not what you're looking for?
How would the following proof be detailed if the commutative axioms did not exist? Explain your answer.
Prove that for all real numbers r, s, t, and u:
(r + s)(t + u) = rt + ru + st + su
Commutative Axiom for Multiplication:
For any two real numbers r and s, the following equation holds:
rs = sr
Commutative Axiom for Addition:
For any two real numbers r and s, the following equation holds:
r+s = s+r
Purchase this Solution
Solution Summary
Proof without using commutative axioms is typified.
Solution Preview
For any three real numbers a, b, c, we have two distributive axioms for multiplication over ...
Purchase this Solution
Free BrainMass Quizzes
Geometry - Real Life Application Problems
Understanding of how geometry applies to in real-world contexts
Probability Quiz
Some questions on probability
Multiplying Complex Numbers
This is a short quiz to check your understanding of multiplication of complex numbers in rectangular form.
Solving quadratic inequalities
This quiz test you on how well you are familiar with solving quadratic inequalities.
Graphs and Functions
This quiz helps you easily identify a function and test your understanding of ranges, domains , function inverses and transformations.