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First Derivative Test and Maximizing Revenue Functions

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Using the first derivative test, find the critical values and intervals where the function is increasing.

y = x^2 - 6x + 2

Using the first derivative test, find the critical values and intervals where the function is increasing.

y = x^3 - 27x + 2

If the demand function is given by p = - 0.4x + 24, find the value at which the revenue function is a maximum.

Find the value at which the revenue is maximized. If the revenue function is R(x) = -x^3 + 36x.

Find where the marginal cost is at a minimum, where x is output in thousands of dollars and x is between 0 and 50. If the cost function is: C(x) = 0.4490x - 0.01563x^2 + 0.000185x^3.

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This solution shows how to use the first derivative test and how to maximize revenue or minimize cost in an attached Word document.

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