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Monopoly for Profit-Maximizing Outputs

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Part A: I attempted to find the profit-maximizing output and I got 42.857. From there I came up with a price of -25.71 (I don't feel that this is correct). After that I tried to find the profit, but when I went back to substitute my quantity (Q1) back into the profit equation I had a Q and I don't have a value for Q.

Part C: I don't understand how to take the number from the monopoly and use them for perfect competition.

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Hello!
Here are your answers.

Part A
Here, we must first write the profit function. Revenue is P*Q (where P is given by the demand function) and cost is given by the cost function. Therefore, the profit function is:

Profit = P*Q - C = (660 - 16Q)Q - 900 - 60Q - 9Q^2 = 660Q - 16Q^2 - 900 - 60Q - 9Q^2
[the ^ symbol means "to the power of"]

In order to find the profit-maximizing quantity, we find the derivative of this function and equate it to zero. The derivative with respect to Q is:

660 - 32Q -60 - 18Q = 600 - 50Q

When equating it to zero, we get:

600 - 50Q = 0
50Q = 600
Q = 12

So the quantity is 12. Plugging this value into the demand function, we get that the price will be P = 660 - 16*12 = $468. Finally, the profit can be found by plugging Q=12 into the profit function we found above.

Profit = 660*12 - 16(12)^2 - 900 - 60*12 - 9(12)^2 = $2,700

So profit will be ...

Solution Summary

The expert examines monopoly for profit-maximizing outputs.

$2.19
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