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    Equation of a straight line which is tangent to a curve

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    For the curve f(x) = x - 1/3x^2 (one third x squared), find the equation of the straight line which is tangent to this curve at the point x = 1.
    See attachment for diagram.

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    For the curve f(x) = x - 1/3x^2 (one third x squared), find the equation of the straight line which is tangent to this curve at the point x = 1.

    Equation of the curve= f(x) = x - 1/3x^2
    y= x- 1/3 x ^2
    Finding derivative is easy
    Derivative of x ^n is n x ^ (n-1)
    Thus derivative of x ^2 is
    2 x ^(2-1)= 2 x ^ 1 that is 2x
    Derivative of x is
    x= x ^1
    therefore ...

    Solution Summary

    Finds the equation of the straight line which is tangent to the curve f(x) = x - 1/3x^2.

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