Equation of the Line Tangent to the Curve

Hi, this was your response

since dy/dx means the slope of a tangent to the curve at a certain point

there fore dy/dx= (3 x^2)- (6*2*x^1)
dy/dx = (3x^2) - (12x)

Equation of the line tangent to the curve= dy/dx = 3x^2 - 12x

Thanks
Ramesh

but can you please explain further how you got dy/dx= (3 x^2)- (6*2*x^1) from y = x^3 - 6x^2 to come up with dy/dx = (3x^2) - (12x)

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Please see the attached file.

Find an equation of the line tangent to the curve y = x^3 - 6x^2 at its point of inflection. (^ means exponent).
Hi, this was your response

since dy/dx means the slope of a tangent to the curve at a certain point

there fore dy/dx= (3 x^2)- (6*2*x^1)
dy/dx = (3x^2) - (12x)

Equation of the line tangent to the curve= dy/dx = 3x^2 - 12x ...

Equations of the line tangent to the curve are provided. The derivative is given.

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