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    Equation of the Line Tangent to the Curve

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    Hi, this was your response

    since dy/dx means the slope of a tangent to the curve at a certain point

    there fore dy/dx= (3 x^2)- (6*2*x^1)
    dy/dx = (3x^2) - (12x)

    Equation of the line tangent to the curve= dy/dx = 3x^2 - 12x

    Thanks
    Ramesh

    but can you please explain further how you got dy/dx= (3 x^2)- (6*2*x^1) from y = x^3 - 6x^2 to come up with dy/dx = (3x^2) - (12x)

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    Solution Preview

    Please see the attached file.

    Find an equation of the line tangent to the curve y = x^3 - 6x^2 at its point of inflection. (^ means exponent).
    Hi, this was your response

    since dy/dx means the slope of a tangent to the curve at a certain point

    there fore dy/dx= (3 x^2)- (6*2*x^1)
    dy/dx = (3x^2) - (12x)

    Equation of the line tangent to the curve= dy/dx = 3x^2 - 12x ...

    Solution Summary

    Equations of the line tangent to the curve are provided. The derivative is given.

    $2.49

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