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    Find an equation of a tangent line.

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    Find an equation of the line tangent to the curve y = x^3 - 6x^2 at its point of inflection. (^ means exponent).

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    since dy/dx means the slope of a tangent to the curve at a certain point

    there fore dy/dx= (3 x^2)- (6*2*x^1)
    dy/dx = (3x^2) - (12x)

    Equation of the line tangent to the curve= dy/dx = 3x^2 - 12x

    If there is a point of inflection on this curve then it must be at a point where the second derivative is zero.
    i.e A point of ...

    Solution Summary

    The equation of a tangent line is found.