Find an equation of the line tangent to the curve y = x^3 - 6x^2 at its point of inflection. (^ means exponent).© BrainMass Inc. brainmass.com March 4, 2021, 7:58 pm ad1c9bdddf
since dy/dx means the slope of a tangent to the curve at a certain point
there fore dy/dx= (3 x^2)- (6*2*x^1)
dy/dx = (3x^2) - (12x)
Equation of the line tangent to the curve= dy/dx = 3x^2 - 12x
UPDATE FROM OTA:
If there is a point of inflection on this curve then it must be at a point where the second derivative is zero.
i.e A point of ...
The equation of a tangent line is found.