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Substituting variable

Please show how to solve y'' - 3y^2=0, substituting v=y' so y'' = v dv/dy
Initial conditions are y(0) =2 and y'(0)=4

I got it as far as dy/dx = (y^3 +c)^1/2 but that might be wrong!

Solution Summary

This solution is comprised of a detailed explanation to show how to solve y'' - 3y^2=0, substituting v=y' so y'' = v dv/dy.

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