Prove algebraically that for complex numbers,
|z1| - |z2| (is less than or equal to) |z1 + z2| (is less than or equal to) |z1| + |z2|
Interpret this result in terms of two-dimensional vectors. Prove that
|z-1| < |sqrt(z^2 - 1) < |z + 1|, for H(z) > 0.
Show that complex numbers have square roots and that the square roots are contained in the complex plan. What are the square roots of i?
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The solution ...
The solution illustrates how to show that any complex number has a square root, and how to construct an analytic function.