CLEP exam sample questions
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Can you please help me with these. I can not get these and I am trying to study for the clep exam. Do not do the circled problems only the ones listed below. Thank you for help. Please show step so that I can understand better.
129
1. a) 6, b) 12, c) 16, d) 20
2. a) 24, b) 26
3. a) 35, b) 36
4. a) 46, b) 48
P. 143
6.b) 50
7. #82
P. 151
8. # 24
9. # 30
10. # 44,
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Solution Summary
This shows a variety of sample CLEP questions regarding complex numbers.
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6.)
(3+7i) - (2+5i)
= 3 + 7i - 2 - 5i
= (3-2) + (7-5)i
= 1 + 2i --Answer
12.)
(3i)(5i)
= 3i*5i
= 15*i^2
= 15*(-1) [Because, i^2 = -1]
= -15 --Answer
16.)
(2-i)(-5+6i)
= 2*(-5) + 2*6i - i*(-5) - i*6i
= -10 + 12i + 5i - 6i^2
= -10 + 17i - 6*(-1) [Because, i^2 = -1]
= -10 + 17i + 6
= -4 + 17i --Answer
20.)
(3+8i)(3-8i)
= 3^2 - (8i)^2
[Because, (a+b)(a-b) = a^2 - b^2]
= 9 - 64*i^2
= 9 - 64*(-1)
= 9 + 64
= 73 --Answer
24.)
(3-5i)/(2-i)
Multiply in numerator and denominator by the conjugate of denominator
=[(3-5i)*(2+i)]/[(2-i)*(2+i)]
= [ 3*2 + 3*i - 5i*2 - 5i*i]/(2^2 - i^2)
= [6 + 3i - 10i - 5*i^2]/(4 - (-1)) [Because, i^2 = -1]
= [6 -7i -5*(-1)]/(4+1)
= [6 -7i + 5]/5
= (11 - 7i)/5 --Answer
26.)
(-5+10i)/(3+4i)
Multiply in numerator and denominator by the conjugate of denominator
=[(-5+10i)*(3-4i)]/[(3+4i)*(3-4i)]
= [-5*3 - 5*(-4i) + 10i*3 + 10i*(-4i)]/(3^2 - (4i)^2)
= [ -15 + 20i + 30i - 40*i^2]/(9 - 16*i^2)
= [ -15 + 50i - 40*(-1)]/(9 - 16*(-1))
= [-15 + 50i + 40]/(9+16)
= (25 + ...
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