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Solve Given Differential Equation by Undetermined Coefficients : y'' + 4y = 3sin(2x)

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Could you provide assistance on setting up and working of the problem.

y'' + 4y = 3sin(2x)

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A differential equation is solved. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

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Hi, here is the solution.

The Auxillary Eqation is d^2y/dx^2 +4y =0

(d^2/dx^2 +4)y =0

m^2 +4 =0 Where d^2/dx^2 = m

m^2 = -4

m = +/- sqrt(-4)

m = +/- sqrt(-1) sqrt(4)

m = +/- 2i [ since sqrt(-1) = i]
...

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