# Prove Compactness of a Closed Subset

Prove that any closed subset of compact metric space is compact by using Theorem 2.

Theorem 2: A subset of S of a metric space X is compact if, and only if, every sequence in S has a subsequence that converges to a point in S.

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Proof:

We consider a closed subset S in a compact metric space C. Then we consider any sequence {x_n} in S. Since {x_n } ...

#### Solution Summary

The solution proves a closed subset of a compact metric space is also compact.

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