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    Proving for Compactness and Convergence of Sequences

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    Prove that [0,1]^n is compact for any number (n e N) by using theorem 2. (see attached file)

    Theorem 2: A subset S of a metric space X is compact if, and only if, every sequence is S has a subsequence that converges to a point in S.

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    Solution Summary

    The solution proves [0,1]^n is compact through a given theorem.