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Horse Velocity Using Derivatives

The problem is in JPEG, thank you.

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Hi, this is a great question. Start out by making your own plot of the data. I did not include a plot, because I think it is beneficial for you to do this step. If you plot the given data (distance vs. time), you will see that it is pretty much a line. The general rule is that if a distance vs. time plot is a straight positive sloping line, then the corresponding velocity is positive and constant. Therefore, the velocity in the middle can be calculated by taking the difference of two of the distances and dividing it by the corresponding time points in seconds. Taking the first and last ...

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