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Velocity and Acceleration

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1. The distance-time relationship for a moving object is given by s(t) = kt2 + (6k^2 - 10k)t + 2k, where k is a non-zero constant

a) show that acceleration is constant

b) Find the time at which the velocity is zero, and determine the position of the object when this occurs.

2. An object moves so that its velocity, v, is related to its position, s, according to v = (b^2 + 2gs)^1/2, where b and g are constants. Show that the acceleration of the object is constant.

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Solution Summary

Velocity and accelerationare investigated using functions and derivatives.

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