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Resultant force and work

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The speed of a 4Kg object is given by v=(2t)m/s,where t is in seconds. At what rate is the resultant force on this object doing work at t=1 second?

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Solution Summary

This solution is provided in 114 words. It discusses acceleration and velocity in relation to time using derivatives and calculates work with respect to time.

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Force = m*a (mass times acceleration)

= (4 kg)(2 m/s^2) = 8 N

The acceleration is the first derivative of velocity ...

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