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A number of simple Q & A's involving acceleration & force

14. An automobile traveling on a straight, level road at 14 m/s speeds up to 25 m/s in 30 seconds. What was the magnitude of the auto's acceleration?

15. Two opposite forces of 6.0 N and 4.0 N act on a 2.0 kg object. What is its acceleration?

16. An automobile with a mass of 100 kg is moving north on a level highway with a constant velocity of 80 km/h. What is the net force acting on the automobile?

Solution Preview

14. An automobile traveling on a straight, level road at 14 m/s speeds up to 25 m/s in 30 seconds. What was the magnitude of the automobiles acceleration?

Acceleration (a) is rate of change of velocity, thus we can express this as

a = change in velocity/change in time = Delta(v)/Delta(t)

Change in velocity is Delta(v) = final velocity - initial velocity = 25 - 14 = 11 m/s

Change in time Delta(t) = 30 - 0 = 30 s

a = 11/30 = 0.367 ...

Solution Summary

Change of velocity is examined over a known time to derive the acceleration of that body, Newtons second Law is used to detemine the net acceleration of a body of known mass when two opposing unequal forces are applied to that body and the net force acting on a body moving at constant veloicty is shown to be zero

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