The speed of a 4.0kg object is given by (2t) m/s, where t is in seconds. At what rate is the resultant force on this object doing work at t = 1 second?
a) 48 W
b) 40 W
c) 56 W
d) 16 W
A 10kg object is initially at the top of a rise, at point A. It then moves down to point B. Choose point B to be your zero level for gravitational potential energy. Find the change in potential energy of the object if point B is 10m lower than point A?
OTA: Please take this problem only if you can show step by step problem solving and equations used. Thank you.
Given: v= 2t so initial velocity at t=0 is: Vo= 0
At t= 1 sec, Vf= 2 m/sec.
Acceleration is: a= (Vf - Vo)/t = (2 m/sec - 0)/( ...
This solution is provided in 156 words. It uses equations for acceleration, resultant force, and power to find the rate of work. It also calculates loss of potential energy.