# Differential equations

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(1) Find the general solution of x^2y" - xy'+ y = x^2, x > 0

(2) The initial value problem of y"'+y' = 2 + sin(x), y(0)=0,y'(0)=1, y"(0)=-1.

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#### Solution Summary

The solution provides an example of finding a general solution for a differential equation and solving an initial value problem.

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