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    Advanced Calculus: The Existence Theorem for Nonlinear Differential Equations

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    Let g(x,y) be Lipschitz continuous. Let ? (x) = y , and for n > 0 define ? (x) = y +
    Prove that ? (x)  ?(x) on [x - , x + ], for some > 0, where ?(x) solves the ODE ?'(x) = g(x, ?(x)), and ?(x ) = y

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    https://brainmass.com/math/calculus-and-analysis/existence-theorem-nonlinear-differential-equations-19101

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    Proof:
    is Lipschitz continuous, then it satisfies the Lipschitz condition. There exists , such that is continuous, so we can suppose is continous in a rectangular region , . Since is a closed region, can reach its maximum value in this ...

    Solution Summary

    The existence theorem for nonlinear differential equations is discussed.

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