Explore BrainMass
Share

# Quadratic equation of a rocket

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

Find the time based on the information given. Distance-100 miles, Rate 109.5509...the time is ____hours.

A rocket is launched from the top of an 60 foot cliff with an initial velocity of 110 feet per second. The height, h, of the rocket after t seconds is given by the equation h=-16t^2+110t+60. How long after the rocket is launched will it be 20 feet from the ground?

#### Solution Preview

First question
The rate here referes to the velocity v, i.e. the rate of change of distance x with respect to time t. Now, we
know that
v =
x
t
(1)
so the time is
t =
x
v
=
100 miles
109.5509 miles/hour = 0.9128176948 hours = 54.76906169 min. (2)
Second question
When the rocket is 20 ft ...

#### Solution Summary

This solution provides calculations for a quadratic equation with rockets. A step-by-step analysis is provided, with explanations.

\$2.19