A projectile is launched from a platform 20 feet high with an initial velocity of 112 feet per second, The height h of the projectile at t seconds after launch is given h= - 16t^2 + 112t +20 feet.
a. How many seconds after launch does the projectile attain maximum height?
b. What is the maximum height?
The solution gives detailed steps on finding the maximum height for a specific example using first derivative test.