The number of cans in the layers of a display at a supermarket forms an arithmetic sequence. The bottom layer has 28 cans; the next layer has 25 cans, the next layer has 22 cans and so on until there is 1 can at the top of the display. 1) How many total cans are in the display? 2) How many rows of cans are in the entire display if the bottom row has 28 cans? 3) What rule can you write to determine how many cans would be in the "nth" row of the display? 4) The store manager wants to make a giant display, if he can build a display that is 50 cans tall, how many cans will be in the bottom row?
(1 and 2) a1 = 28, a2 = 25, an = 1
d = a2 - a1 = -3
an = a1 + (n - 1)d
1 = 28 + (n - 1)(-3)
-27/-3 = ...
A Complete, Neat and Step-by-step Solution is provided.