Write the equation of a circle centered at (3,4) with a radi
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Write the equation of
a. a circle centered at (3,4) with a radius 5
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a. The equation for a circle is
(x - h)2 + (y - k)2 = r2
where h and k are the x- and y-coordinates of the center of the circle and r is the radius. So in this problem the equation for the circle centered at (3,4) and r = 5 is:
(x - 3)2 + (y - 4)2 = 25
b. Let y = ax + b. This line goes thru (-1,3) and (5,18) hence:
-a + b = 3 OR b = a +3
5a + b = 18
Substitute b = a + 3 into the above:
5a + a + 3 = 18
Hence 6a = 15 or a =15/6 =2.5
And therefore b = 5.5
The line has the form y = 2.5x + 5.5
c. Choose some point having coordinates (x,y). The distance between this point and (-5,4) is given by:
The distance between point (x,y) and (3,16) is given by
Equating these distances, since the point is to be equidistant from the two given points, we have:
=
Squaring both sides, we have:
Reference:
http://www.tpub.com/math2/10.htm
Substitute one into the other:
Hence the points of intersection are (0.5,0.87) and (-0.5,-0.87)
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