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Sum of infinite geometric series

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A regular hexagon is inscribed in a circle of radius 100. The area of that hexagon outside the square is shaded. Another circle is inscribed in the hexagon, and hexagon is inscribed in the second circle. The area of the second circle which lies outside the hexagon is shaded. This process continues to infinity.
What is the sum of all shaded areas?

Radius of 1 = 100
Radius of 2 = ______
Radius of 3 = _______
Radius of 4 = ________
Side of hexagon 1st =_________
Side of hexagon 2nd = ________
Side of hexagon 3rd = ________
Side of hexagon 4th = _______
Area of Circle 1 = ________
Area of Circle 2 = ________
Area of Crcle 3 =________
Area of Circle 4 = _______
Area of Hexagon 1 = _______
Area of Hexagon 2 =______
Area of Hexagon 3 = ______
Area of Hexagon 4 = _________
Difference of 1st =_________
Difference of 2nd =_________
Difference of 3rd =_________
Difference of 4th =________

Each new one is _________of the previous area.
Sum of all areas = ___________

Is there any relationship concerning the areas as the number of sides of the inscribed figure increases? If so what would you predict would be the area sum for 8 or 9 sides?_________

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Solution Summary

This is an infinite geometric series question using the hexagons and circles inscribed inside of each other.

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The sum of an infinite Geometric Series
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A regular hexagon is inscribed in a circle of radius 100. The area of that hexagon outside the square is shaded. Another circle is inscribed in the hexagon, and hexagon is inscribed in the second circle. The area of the second circle which lies outside the hexagon is shaded. This ...

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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
  • "Thank you very much for your valuable time and assistance!"
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