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Finding equations of line

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Complete the equation of the line L satisfying each of the following sets of geometric conditions by determining the values of b1 and bo.

1. L has a slope of ¾ and x-intercept of (-4,0), y=b1x+bo
b1=
bo=

2. L passes through (2,1) and is perpendicular to the line with the equation 3x-2y=5, y=b1x+bo
b1=
bo=

3. L passes through (0,-4) and is parrellel with the line 3x-y=6, y=b1x+bo
b1=
bo=

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The solution explains the steps for determining the equation of line satisfying the given conditions.

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Solution:

1) L has a slope of ¾ and x-intercept of (-4,0) y=bix+bo
Equation of a line L with slope m and which passes through (x1, y1) is given by
y-y1=m(x-x1)
(x1, y1) is (-4,0)
m=3/4
Put these values in the above equation
y-0=(3/4)*[x-(-4)]
y=(3/4)x+3

Comparing it with given format y=bix+bo, we get
bi=3/4
bo=3

2)L passes through (2,1) and is perpendicular to the line with the equation ...

Solution provided by:
Lokesh Jain, MSc
Education
  • BEng (Hons) , Birla Institute of Technology and Science, India
  • MSc (Hons) , Birla Institute of Technology and Science, India
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