Need help on following problems, have tried to work them out and am confused..
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#12 (Commutative & Associative Properties)
-8 + 12 - 9 - 15 + 6 - 22 + 3
#34 (Distributive Property)
Use distributive property to write each sum or difference as a product.
7b - 49
#54 Multiplication Property of Zero
x * 5 = 5x
#26 (Using the Properties in Computation)
Perform each computation. Make use of appropriate rules to simplify each problem
33 * 2 - 12 * 33
#38 (Combining like terms)
-19m - (-3m)
#100 Simplify each expression
2(xsubscript 2 - 3)-(6xsubscript 2 - 2) + 2(-7xsubscript 2 - 4)
#36 (Add and Sub of polynomials)
(2x - 5) - (xsuscript2 - 3x + 2)
#42 Perform and indicate operations vertically
Subtract
-3xsubscript 2 + 5x - 2
xsubscript 2 - 5x - 6
#56 Multiplication of polynomials
(xsubscript2 - 3x + 2)(x - 4)
#92 Perform the indicated operations. A variable used in an exponent represents and integer; a variable used as a base represents a nonzero real number.
(bsubscript3z - 6) -(4bsubscript3z - 7)
#24 The FOIL method--find each product.
(7a - 2x)(x + a)
#34 The Square of a Binomial. Find the square of each sum or difference
(3w - 2x)subscript2
#44 Product of a sum and a difference
(3 + 5x)(3 - 5x)
NOTE WHERE I HAVE TYPED IN SUBSCRIPT AND THE NUMBER, I DID THAT BECAUSE I DONT KNOW HOW TO MAKE THE NUMBER SMALL TO SHOW HOW IT IS WRITTEN IN MY PROBLEM. THANK YOU FOR ALL YOUR HELP.
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Solution Summary
The expert examines commutative and associative properties.
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Please see the attached file. Hope it helps.
#12 (Commutative & Associative Properties)
-8 + 12 - 9 - 15 + 6 - 22 + 3
=4-9-15+6-22+3
=-5-15+6-22+3
=-20+6-22+3
=-14-22+3
=-36+3
=-33
#34 (Distributive Property)
Use distributive property to write each sum or difference as a product.
7b - 49
=7(b-7)
#54 Multiplication Property of Zero
x * 5 = 5x
As ...
Education
- BSc , Wuhan Univ. China
- MA, Shandong Univ.
Recent Feedback
- "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
- "excellent work"
- "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
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- "Thank you very much for your valuable time and assistance!"
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