Purchase Solution

Half-wave unregulated power supply

Not what you're looking for?

Ask Custom Question

Design a half-wave unregulated power supply to give VL = 15V at IL = 10mA with deltav <= 0.1V. Assume a 120V, 60Hz supply. What is the regulation of the power supply?

Attachments
Purchase this Solution
Solution Summary

"... after filtering through capacitance, there is output dc voltage with ripple (0.1*100/15 = 0.6%)."

Solution Preview

Given,
Input voltage = 120 V
Output voltage (VL) = 15 V

It is clear that output voltage will be the peak voltage = (Vp_out) = 15 V
Input peak voltage (Vp_in) = 120*sqrt(2) = 169.7 V

Hence, turns ...

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
Recent Feedback
  • " In question 2, you incorrectly add in the $3.00 dividend that was just paid to determine the value of the stock price using the dividend discount model. In question 4 response, it should have also been recognized that dividend discount models are not useful if any of the parameters used in the model are inaccurate. "
  • "feedback: fail to recognize the operating cash flow will not begin until the end of year 3."
  • "Answer was correct"
  • "Great thanks"
  • "Perfect solution..thank you"
Purchase this Solution
Free BrainMass Quizzes
Architectural History

This quiz is intended to test the basics of History of Architecture- foundation for all architectural courses.

Air Pollution Control - Environmental Science

Working principle of ESP

View More Free Quizzes
Related BrainMass Solutions

  • Power supplies regulated & unregulated problems and solutions

    here Power supply design (unregulated part of supply shown below).

  • Wave Energy Investment

    (i) The match between variations in demand and supply. (ii) The match between the locations of demand and supply. (iii) Environmental factors. (iv) Current development in wave power technologies.

  • Proper Bridge Rectifier for PSU

    519471 Proper Bridge Rectifier for PSU FIGURE 1(a) shows a power supply using a full-wave bridge rectifier circuit.

  • Diodes and Path of Current

    Maybe your instructor gave you a different formula for finding the capacitor value given the AC voltage, type of supply (half-wave or full-wave), the load current, the frequency, the desired maximum ripple, etc., but it should give a similar answer.

  • Problems on Radiation Physics

    The peak power of a 6ft. diameter antenna is 10 watts and its duty cycle is 0.250. The wave length is 0.03m/cycle. Find the power density in mw/cm2 at 50 meters from the antenna. 2.

  • AC sine wave

    The full wave rectifier flips the negative half cycles of the sine wave and turn them into positive half cycles. So the output of the full wave rectfier is a train of positive sine half cycles.

  • Working with a full-wave rectifier circuit

    (For the full-wave rectifier circuit shown below, the supply voltage is 18-V rms sinusoidal, Vdo is approximately 0.7V and R=120. What is the value for PIV?)

  • Received power of half-wave dipole antennas

    329165 Received power of half-wave dipole antennas Assume that two antennas are half-wave dipoles and each has a directive gain of 3dB.

  • Calculate the delay angle (alpha)

    11994 Calculate the delay angle (alpha) The three-phase half-wave converter in figure below is operated from a three-phase wye-connected 220V, 60 Hz supply and the load resistance is R=10 ohms.

View More Related Solutions