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Working with a full-wave rectifier circuit

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Please check my work and if incorrect give me the correct answer

Please refer to the problem stated in the attached file.

(For the full-wave rectifier circuit shown below, the supply voltage is 18-V rms sinusoidal, Vdo is approximately 0.7V and R=120. What is the value for PIV?)

This is my solution:
Piv=2Vs-Vd
2*18sqrt2-.7=50.21

The answer is B

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Peak inverse voltage is the maximum value of the reverse voltage present across the diode during the half cycle in which it is not conducting.

If we calculate the maximum reverse ...

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