Explore BrainMass
Share

Explore BrainMass

    Basic electricity - 3 phase installation powered

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Consider the following:
    A 3 phase installation powered by 400V 50Hz is composed of 6 machines.
    (Please see the attached table)

    Find:
    a) Total apparent power
    b) Total absorbed current (line current)
    c) Installation power factor
    d) The power of the capacitors that should be installed to have a power factor of 0.95
    e) Total absorbed power after the power factor as been corrected.

    A step by step explanation is required.

    © BrainMass Inc. brainmass.com October 9, 2019, 10:28 pm ad1c9bdddf
    https://brainmass.com/engineering/power-engineering/basic-electricity-phase-installation-powered-221429

    Attachments

    Solution Preview

    ===============================================================================

    Equations Used: For a 3-phase installation
    ---------------

    P = sqrt(3)* V * I * (PF) Watts, PF = Power factor = Cos (Theta)

    S^2 = P^2 + Q^2 VA

    PF = Cos(Theta) = P/S

    I = P / [sqrt(3)* V * (PF)] Amps

    V = 400 Volts

    Now, let us compute all the unknown quantities for all the 6 machines using the above equations.

    N = 2458 for all except N = 2.458 for I(Current computation)
    ---------------------------------------------------------------------

    Machine 1:
    ----------

    P = 5N; Q = 2N

    Hence, S = 5.39N; PF = 0.93;
    I = 0.00776N = 19.1 A
    ...

    Solution Summary

    Three phase installation powered is examined. The total apparent power is analyzed.

    $2.19