# Basic electricity - 3 phase installation powered

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Consider the following:

A 3 phase installation powered by 400V 50Hz is composed of 6 machines.

(Please see the attached table)

Find:

a) Total apparent power

b) Total absorbed current (line current)

c) Installation power factor

d) The power of the capacitors that should be installed to have a power factor of 0.95

e) Total absorbed power after the power factor as been corrected.

A step by step explanation is required.

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##### Solution Summary

Three phase installation powered is examined. The total apparent power is analyzed.

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Equations Used: For a 3-phase installation

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P = sqrt(3)* V * I * (PF) Watts, PF = Power factor = Cos (Theta)

S^2 = P^2 + Q^2 VA

PF = Cos(Theta) = P/S

I = P / [sqrt(3)* V * (PF)] Amps

V = 400 Volts

Now, let us compute all the unknown quantities for all the 6 machines using the above equations.

N = 2458 for all except N = 2.458 for I(Current computation)

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Machine 1:

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P = 5N; Q = 2N

Hence, S = 5.39N; PF = 0.93;

I = 0.00776N = 19.1 A

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