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    Wheatsone bridge thermistor ADC

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    A thermistor has a resistance of 9.0 k ohms in ice-water and 0.5 k ohms in boiling water. The thermistor obeys the law... see attachment

    © BrainMass Inc. brainmass.com June 2, 2020, 12:53 am ad1c9bdddf
    https://brainmass.com/engineering/electrical-engineering/565750

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    a.
    R(T) = K*exp(B/T)

    T1 = 0+273 = 273 K
    T2 = 100+273 = 373 K
    R(T1) = 9 ohm
    R(T2) = 0.5 ohm

    Hence,
    9 = K*exp(B/273)
    0.5 = K*exp(B/373)

    9/0.5 = exp(B/273)/exp(B/373)
    => 18 = exp(B*(1/273 - 1/373))
    => ln(18) = B*(1/273 - 1/373)
    => B = ln(18)/(1/273 - 1/373) = 2943.24

    Hence,
    9 = K*exp(2943.24/273)
    => K = 9 /exp(2943.24/273) = 1.87*10^(-4)

    b.
    As, Vo =0 for T = 0 + 273 = 273 K,
    This is a balanced wheat stone bridge at 0 degree C
    Hence,
    R2 = R3 = R4 = RT(0) = 9 ohm

    Let us assume, when Vo=1V, i.e., T = 50+273 = 323 K, ...

    Solution Summary

    Variation of resistance of a thermistor with temperature is established. The thermistor utilized in a Wheatstone bridge as a transducer, hence other resistances are estimated and potential difference across the bridge is estimated.

    This system is used as an input to a 12 bit ADC. Temperature change/bit is estimated. A successive approximation method is used for ADC.

    $2.19

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