Combinational Arithmetic Circuit : Sum of n kbit numbers
The sum of n kbit numbers can be computed by a combinational arithmetic circuit as follows.
Assume that n is an exact power of 2. The circuit consists of a complete binary tree of ripplecarry adders, in which each node in the tree adds two numbers and produces a sum which is fed to its parent. The n/2 leaves of the tree input the n kbit numbers, and the total sum is produced as output by the root. Each ripplecarry adder is as small as possible while still ensuring that the sum is correctly computed.
[a] What is the maximum number of bits in the sum of the n kbit numbers?
What is the number of full adders in any ripplecarry adder at height h in the tree, where we view leaves as having height 0?
[b] Give a tight asymptotic upper (bigOh) bound in terms of n and k, on the size of this circuit (definition below). Briefly explain your answer.
[c] Give a tight asymptotic upper bound in terms of n and k on the depth of this circuit (definition below). Briefly explain your answer.
[d] Describe a combinational circuit that computes the sum of n kbit numbers more efficiently. Analyze the size and depth of this circuit.
Circuit Depth :
As in the case of the comparison networks, we measure the propagation delay of a combinational circuit in terms of the largest number of combinational elements on any path from the inputs to the outputs. Specifically, we define the depth of a circuit, which corresponds to its worstcase "running time", inductively in terms of the depths of its constituent wires. The depth of an input wire is 0. If a combinational element has inputs x1, x2,..., xn at depths d1, d2,...,dn respectively, then it's outputs have depth (max{d1, d2,..., dn}+1).
The depth of a combinational element is the depth of its outputs. The depth of a combinational circuit is the maximum depth of any combinational element in it. Since we prohibit combinational circuits from containing cycles, the various notions of depth are well defined. If each combinational element takes constant time to compute its output values, then the worstcase propagation delay through a combinational circuit is proportional to its depth.
A combinational circuit can sometimes compute faster that its depth. Suppose that a large subcircuit feeds into one input of a 2input AND gate but that the other input of the AND gate has a value of 0. The output of the gate will then be 0, independent of the input being applied to the circuit, and the abstraction of depth as the "running time" of the circuit is therefore quite reasonable.
Circuit Size :
Besides circuit depth, there is another resource that we typically wish to minimize when designing circuits  the size of a combinational circuit, which is defined as the number of combinational elements it contains. Intuitively, circuit size corresponds to the memory space used by an algorithm.
This definition of circuit size is not particularly useful for small circuits. After all, since a full adder has a constant number of inputs and outputs and computes a welldefined function, it satisfies the definition of a combinational element. A full adder built from a single full adder combinational element therefore has size 1. In fact, according to this definition, any combinational element has size 1.
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[a] When you add two numbers of kbits each, it can result in a number that might require (k+1) bits to store. For example, when you add two 8bits unsigned numbers, the maximum possible result of addition could be 510 that would require 9 bits to store it.
Given that n is an exact power of 2, so we can write "n = 2^M, where M >= 0".
Consider the following example of n kbit numbers addition using given combinational circuit, with "n = 8".
M = lg(n) = lg(8) = 3, where lg means log_base_2.
numbers size = (k+3) bits

Height(h)=2 : addition of 1 pair (2 numbers)

numbers size = (k+2) bits

Height(h)=1: addition of 2 pairs (4 numbers)

numbers size = (k+1) bits

Height(h)=0: addition of 4 pairs (8 numbers)

numbers size = (k+0) bits
At leaf level (Height=0), we add (n/2) pairs (n numbers) and thus use (n/2) ripple carry adders (henceforth referred to as RCA) generating (n/2) (k+1)bit numbers.
At next level (Height=1), we add (n/4) pairs (n/2 numbers generated from additions at lower level) and thus use (n/4) RCA generating (n/4) (k+2)bit numbers.
And so on, till we add only 2 numbers at root level and generate single number indicating the result of summing initial n numbers.
We can easily notice that at each level of addition the size of numbers increases by 1 bit (to make provision for storing the largest possible number resulting from addition).
Total level of additions = M = lg(n)
Hence, maximum number of bits in the sum of the n kbit numbers = ...
Solution Summary
Solution explains in detail (with examples as needed) how the answers are arrived at, be it computing the maximum number of bits in the final sum, or finding the upper bounds on circuit depth and size.